When every member of a linker list is aligned by the compiler, we can no
longer rely on the sizeof of the struct to determine the number of
entries.
For example, if the struct size is 0x90 but every entry is aligned to 0xa0
by the compiler, the linker list entries takes more space in memory and
the calculation of the number of entries is incorrect. For example, we may
see 0x12 entries when there are only 0x11.
This is a real problem. There may be a general solution, although I cannot
currently think of one. So far it only bites with OF_PLATDATA_RT which
creates a pointer to each entry of the 'struct udevice' linker_list. This
does not happen without that option, so it only affects SPL.
Work around it by manually calculating the aligned size of struct udevice,
then using that for the n_ent calculation.
Note: the alignment fix to linker list was here:
0b2fa98aa5e linker_lists: Fix alignment issue
Signed-off-by: Simon Glass <sjg@chromium.org>
static struct udevice_rt *dev_get_rt(const struct udevice *dev)
{
struct udevice *base = ll_entry_start(struct udevice, udevice);
- int idx = dev - base;
+ uint each_size = dm_udevice_size();
+ int idx = ((void *)dev - (void *)base) / each_size;
struct udevice_rt *urt = gd_dm_udevice_rt() + idx;
if (CONFIG_IS_ENABLED(OF_PLATDATA_RT)) {
struct udevice_rt *urt;
+ void *start, *end;
+ int each_size;
void *base;
int n_ents;
uint size;
/* Allocate the udevice_rt table */
- n_ents = ll_entry_count(struct udevice, udevice);
+ each_size = dm_udevice_size();
+ start = ll_entry_start(struct udevice, udevice);
+ end = ll_entry_end(struct udevice, udevice);
+ size = end - start;
+ n_ents = size / each_size;
urt = calloc(n_ents, sizeof(struct udevice_rt));
if (!urt)
return log_msg_ret("urt", -ENOMEM);
#endif
};
+static inline int dm_udevice_size(void)
+{
+ if (CONFIG_IS_ENABLED(OF_PLATDATA_RT))
+ return ALIGN(sizeof(struct udevice), CONFIG_LINKER_LIST_ALIGN);
+
+ return sizeof(struct udevice);
+}
+
/**
* struct udevice_rt - runtime information set up by U-Boot
*