disk: initialize name/part fields when returning a whole disk

When get_device_and_partition() finds a disk without a partition table,
under some conditions, it "returns" a disk_partition_t that describes
the entire raw disk. Make sure to initialize all fields in the partition
descriptor in that case.

The value chosen for name is just some arbitrary descriptive string.

The value chosen for info matches the check at the end of
get_device_and_partition(). However, it's probably not that important;
it's not obvious that the value is really used.

Reported-by: Benoît Thébaudeau <benoit.thebaudeau@advansee.com>
Signed-off-by: Stephen Warren <swarren@nvidia.com>
Reviewed-by: Benoît Thébaudeau <benoit.thebaudeau@advansee.com>
Signed-off-by: Tom Rini <trini@ti.com>

diff --git a/disk/part.c b/disk/part.c
index a0c77ddc9d52161270ff437a6ffafd22f1c445d2..8ba3cdeaa026a119e04dffe094bb4f536cc31384 100644 (file)
--- a/disk/part.c
+++ b/disk/part.c
@@ -561,6 +561,8 @@ int get_device_and_partition(const char *ifname, const char *dev_part_str,
                info->size = (*dev_desc)->lba;
                info->blksz = (*dev_desc)->blksz;
                info->bootable = 0;
+               strcpy((char *)info->type, BOOT_PART_TYPE);
+               strcpy((char *)info->name, "Whole Disk");
 #ifdef CONFIG_PARTITION_UUIDS
                info->uuid[0] = 0;
 #endif